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90 POINTS PLEASE HELP

90 POINTS PLEASE HELP-example-1

2 Answers

5 votes

Answer:

sin/alpha = -0.8

Explanation:

User Ianhanniballake
by
7.8k points
2 votes


sin\alpha = - 0.8

Explanation:

We have ,
cos\alpha = (3)/(5) , where
\alpha is located in IV quadrant! Let's find out value of
sin\alpha :


sin\alpha = \sqrt{1-(cos\alpha )^2


sin\alpha = \sqrt{1-(cos\alpha )^2


sin\alpha = \sqrt{1-((3)/(5) )^2


sin\alpha = \sqrt{1-((9)/(25) )


sin\alpha = \sqrt{((25-9)/(25) )


sin\alpha = \sqrt{((16)/(25) )


sin\alpha = \pm {((4)/(5) )

Value of
sin\alpha is dependent on which quadrant it is . Since, in question it's given that
\alpha is located in IV quadrant , So
sin\alpha is negative i.e.


sin\alpha = - {((4)/(5) )


sin\alpha = - 0.8

Therefore,
sin\alpha = - 0.8 .

User Neil Lunn
by
8.1k points

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