Answer:
Check Explanation
Explanation:
Let the width of the parking lot be x ft
The length of the parking lot be y ft
And let us first assume that the rectangular parking lot is enclosing about the dimension of a length of the parking lot.
That is, (y + x + x) = 300
(y + 2x) = 300
Area of the parking lot = A(x, y) = xy
But from the constraint equation,
y = 300 - 2x
Substituting for y in the Area equation
A(x) = x(300 - 2x) = (300x - 2x²)
A(x) = -2x² + 300x
If we now assume that the rectangular parking lot is enclosing the width side of the parking lot,
(x + y + y) = 300
(x + 2y) = 300
2y = (300 - x)
y = (300 - x)/2
y = 150 - (x/2)
A(x,y) = xy
Substituting for y again
A(x) = x[150 - (x/2)]
A(x) = 150x - (x²/2)
A(x) = (-x²/2) + 150x
So, depending on which side of the rectangle the parking lot is enclosing and which 3 sides make up the 300 ft constraint, the Area can be given in the two forms presented above.
Hope this Helps!!!