Question

a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance travelled in 5s​

Answer 1

a) 10 m/s

b) 25 m

Step-by-step explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

`v=u+at`

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

`a=2 m/s^2` is the acceleration

t = 5 s is the time

So, the final velocity is

`v=0+(2)(5)=10 m/s`

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

`v^2-u^2=2as`

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

`a=2 m/s^2` is the acceleration

v = 10 m/s is the final velocity

Solving for s,

`s=(10^2-0^2)/(2(2))=25 m`