Question

1. a) A baseball player is stealing second base traveling at 4.0 m/s and accelerating at 2.0 m/s- for 3.0

seconds. What is the final speed at the end of the 3.0 s?

Answer 1

10.0 m/s

Step-by-step explanation:

The motion of the player is a uniformly accelerated motion (=at constant acceleration).

Therefore, we can calculate the final speed by using the following suvat equation:

`v=u+at`

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

In this problem:

u = 4.0 m/s is the initial velocity

`a=2.0 m/s^2` is the acceleration

t = 3.0 s is the time

Therefore,

`v=4.0+(2.0)(3.0)=10.0 m/s`

So, the final speed is 10.0 m/s.