Question

0,4 kg block of iron is heated from 295K to 325K. How much heat is absorbed by the iron?

Answer 1

5400 J

Step-by-step explanation:

The amount of heat energy required to increase the temperature of a substance is given by:

`Q=mC\Delta T`

where:

m is the mass of hte substance

C is the specific heat capacity of the substance

`\Delta T` is its change in temperature

For the block of iron in this problem, we have:

m = 0.4 kg is the mass of the block

`C=450 J/kg^(\circ)K` is the specific heat of iron

`\Delta T=325-295=30 K` is the increase in temperature

Therefore, the amount of heat absorbed by the iron is:

`Q=(0.40)(450)(30)=5400 J`