Question

One cubic foot of sand weighs about 90 pounds. Approximate the weight of the cone-shaped pile of sand. Round your answer to the nearest hundred pounds. Please show your work too, thank you. :)

Answer 1

3485.63 pounds

Explanation:

For cone shaped sand:

Height (h) = 3.5 ft

Diameter (d) = 6.5 ft

Therefore, radius (r) = 6.5/2= 3.25 ft

`volume \: of \: sand \\ = (1)/(3) \pi {r}^(2) h \\ \\ = (1)/(3) * (22)/(7) * {(3.25)}^(2) * 3.5\\ \\ = (1)/(3) * 22 * 10.5625 * 0.5\\ \\ = (1)/(3) * 11 * 10.5625 \\ \\ = (1)/(3) * 116.1875 \\ \\ = 38.7291667 \: {ft}^(3) \\ \\ \because \: 1 \: {ft}^(3) = 90 \: pounds \\ \\ \therefore \: 38.7291667 \: {ft}^(3) \\ = 38.7291667 * 90 \ \\ = 3,485.625 \: pound \\ \approx \: 3485.63 \: pounds`

Hence, weight of sand is 3485.63 pounds.