Question

If f(x) = 4x^0 + (4x)^-1, what is the value of f(4)

Answer 1

`(65)/(16)` or 4.0625

Explanation:

To solve this problem, all we have to do is input the value x = 4 into the equation and solve.

f(4) = 4(4)^0 + (4x)^-1

f(4) = 4(1) + 1/4(4)

f(4) = 4 + 1/16

f(4) =
`(64)/(16)` +
`(1)/(16)`

f(4) =
`(65)/(16)`

f(4) = 4.0625