Question

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 265 people entered the park, and the admission fees collected totaled 760.00 dollars. How many children and how many adults were admitted?

Your answer is

Answer 1

Answer: 120 children and 145 adults were admitted that day.

Explanation:

Let x represent the number of children that were admitted that day.

Let y represent the number of adults that were admitted that day.

On a certain day, 265 people entered the park. it means that

x + y = 265

The admission fee at an amusement park is $1.50 for children and $4 for adults. On that day, the admission fees collected totaled 760.00 dollars. This means that

1.5x + 4y = 760- - -- - - - - - - - -- -1

Substituting x = 265 - y into equation 1, it becomes

1.5(265 - y) + 4y = 760

397.5 - 1.5y + 4y = 760

- 1.5y + 4y = 760 - 397.5

2.5y = 362.5

y = 362.5/2.5

y = 145

x = 265 - y = 265 - 145

x = 120

Answer 2

120 children and 145 adults were admitted

Explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of children admitted.

y is the number of adults admitted.

265 people entered the park

This means that
`x + y = 265`

The admission fee at an amusement park is $1.50 for children and $4 for adults. The admission fees collected totaled 760.00 dollars.

This means that
`1.5x + 4y = 760`

So

`x + y = 265`

`1.5x + 4y = 760`

From the first equation:

`x = 265 - y`

Replacing in the second equation:

`1.5x + 4y = 760`

`1.5(265 - y) + 4y = 760`

`397.5 - 1.5y + 4y = 760`

`2.5y = 362.5`

`y = (362.5)/(2.5)`

`y = 145`

`x = 265 - y = 265 - 145 = 120`

120 children and 145 adults were admitted