Question

Find the center of the circle whose equation is (x-2)^2(y-4)^2=9.

A.(-2,-4)
B.(2,4)
C.(4,2)​

Answer 1

B.(2,4)

Explanation:

The equation for a circle is written as

(x-h)^2 +(y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-2)^2+(y-4)^2=9.

Rewriting this equation

(x-2)^2+(y-4)^2=3^2

The center is at (2,4)