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A sample of air has a volume of 140 mL 0.980 atm. At what pressure will its final volume be 50.0 mL at constant temperature?

User WildBill
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Answer:

The new pressure is 2, 74 atm

Step-by-step explanation:

We apply Boyle Mariotte's law, where for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1 = P2xV2 P2=( P1 x V1)/V2 1 L-----1000L--->( 140ml/1000ml)x1L=0,140 L

(50ml/1000ml)x 1L =0,050L

P2= (0,980 atm x 0,140 L)/0,050L= 2, 744 atm

User Persijn
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