Out of 3000 light bulbs that were tested, 126 were defective. find the prbability of defective and non defective

asked Dec 7, 2021 159k views

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Answer:

P(defective) = 126/3000 = 0.042

P(not defective) = 1 - P(defective)

= 1 - 0.042 = 0.958

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