Answer:
The velocity of jet in still air u = 671
The velocity of air v = 75
![(mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnas1vjlt5f0m7r8hh5xunjynk2f8dyq4j.png)
Explanation:
Let the velocity of jet = u
![(mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnas1vjlt5f0m7r8hh5xunjynk2f8dyq4j.png)
the velocity of stream = v
![(mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnas1vjlt5f0m7r8hh5xunjynk2f8dyq4j.png)
Jet travels 2384 miles against a jet stream in 4 hours.
Upstream velocity of the jet is given by,
⇒ u - v =
![(2384)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sxim7fri4845i0pemy7uelca2anfo26jm5.png)
⇒ u - v = 596
--------- ( 1 )
Jet travels 2984 miles along a jet stream in 4 hours.
⇒ Downstream velocity of the jet is given by,
⇒ u + v =
![(2984)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3tqi4zpfg6oppjikxh8znst776vz2ix3ze.png)
⇒ u + v = 746
----------- ( 2 )
by adding equation 1 & 2 we get,
⇒ 2 u = 1342
⇒ u = 671
![(mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnas1vjlt5f0m7r8hh5xunjynk2f8dyq4j.png)
This is the velocity of jet in still air.
Put this value of u in equation 2 we get,
⇒ 671 + v = 746
⇒ v = 75
![(mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnas1vjlt5f0m7r8hh5xunjynk2f8dyq4j.png)
This is the velocity of air.