Question

Hudson and Katie are in a race and Hudson is running at 8-8 feet per sec. Katie gets 30 feet head start and is running in 6.3 feet per sec. How many sconds will it take until hudson and kaite to meet

Answer 1

12s.

Explanation:

Given:

Hudson's velocity, Vh = 8.8 ft/s

Katie's velocity, Vk = 6.3 ft/s

Kate's head start distance, Dk = 30 ft

From the above, Katie and Hudson meet at th = tk = t

But, Dk = Dh + 30

Velocity = Distance/time

t × Vk = Dk

t × Vh = Dh

t × Vk + 30 = Dk

t × Vk + 30 = Vh × t

6.3t + 30 = 8.8t

t = 30/2.5

= 12 s