Question

3n² + 2n - 8=0
Solve each equation with the quadratic formula

Answer 1

-2,4/3

Explanation:

ax²+bx+c=0

`x=(-b \pm√(b^2-4ac) )/(2a) \\3n^2+2n-8=0\\n=(-2\pm√(2^2-4*3*(-8)) )/(2*3) \\n=(-2 \pm √(4+96))/(6) }\\n=(-2 \pm 10)/(6) \\n=(8)/(6) =(4)/(3)\\or~n=(-12)/(6)=-2`