Question

5.5 - Solving Quadratic Equations - Perfect Square Trinomials and Difference of Squares

Factor the following if they are a perfect square trinomial or a difference of squares.
a) x^2 + 24x + 144 = 0
b) 9x^2 - 36x + 36 = 0
c) x^2 - 64 = 0
d) 4x^2 - 81 = 0

Answer 1

Explanation:

(a²-2ab+b²)=(a-b)²

a²+2ab+b²=(a+b)²

i solve b and d

(b)

9x²-36x+36=0

(3x)²+2×3x×-6+(-6)²=(3x-6)²

(d)

a²-b²=(a+b)(a-b)

4x²-81=0

4x²-81=(2x)²-9²=(2x+9)(2x-9)