Question

How many liters of hydrogen gas will be produced at 280.0 K and 96.0 kPa if 40.0 grams of sodium react with excess hydrochloric acid? Write the balanced equation first.

Answer 1

0.0017 litres of H2 will be formed if 40.0 grams of sodium react with excess hydrochloric acid.

The balanced equation for the reaction:

2Na +2 HCl ⇒ H2 +2 NaCl

Step-by-step explanation:

the balanced equation for the reaction:

2Na +2 HCl ⇒ H2 +2 NaCl

data given:

Temperature of the reaction = 280 k

pressure of the reaction = 96 kPa

atomic mass of H2 = 2.01 grams/mole

mass of sodium Na = 40 grams

atomic mass of sodium = 22.98 grams/mole

number of moles =
`(mass)/(atomic mass of one mole)`

Number of moles =
`(40)/(22.98)`

= 1.7 moles of Na will react.

from, the equation 2 moles of Na reacts to form 1 mole of H2

1.7 moles of Na reacts to form x mole of H2

`(1)/(2)`=
`(x)/(1.7)`

x = 0.85 moles of H2 will be formed.

mass of H2 will be calculated by multiplying number of moles with atomic mass of H2

0.85 x 2.01

= 1.708 grams of H2 will be formed.

To convert grams into litre the value in litres is divided by 1000

as 1kg =1000 grams is equal to 1L = 1000 grams

so 0.0017 litres of H2 will be formed.