Answer:
82 2/9 square meters
Explanation:
The problem statement gives us two relations between length and width. We can write those using equations and the variables L and W for length and widh, in meters.
P = 2(L +W) . . . . . . formula for the perimeter of a rectangle
38 = 2(L +W) . . . . . the perimeter is 38 meters
(L -3) = 2(W -2) . . . . length less 3 is twice the difference of wdith and 2.
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Dividing the first equation by 2 gives ...
19 = L +W
Solving this for L gives ...
L = 19 -W
Substituting for L in the second equation, we have ...
(19 -W) -3 = 2(W -2)
16 -W = 2W -4 . . . . . . . simplify
20 = 3W . . . . . . . . . . . add W+4
W = 20/3 . . . . . . . . . divide by 3
L = 19 -20/3 = 37/3 . . . . find L from W
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The area of the farm is the product of length and width:
A = LW = (37/3 m)(20/3 m) = 740/9 m²
A = 82 2/9 m²
The area of the farm is 82 2/9 square meters.