Question

In the balanced chemical reaction shown below, what is the molar ratio of Fe to Al?

Fe2O3(s) + 2Al(s) --> 2Fe (5) + Al2O3 (5)

Answer 1

The molar ratio of Fe to Al in the balanced chemical reaction is 2:1.

Step-by-step explanation:

In the balanced chemical reaction shown, the molar ratio of Fe to Al is 2:1. This means that for every 2 moles of Fe2O3, we need 1 mole of Al to fully react.

For example, if we have 4 moles of Fe2O3, we would need 2 moles of Al to react completely and produce 4 moles of Fe and 2 moles of Al2O3.

Similarly, if we have 1 mole of Fe2O3, we would need 0.5 moles of Al to react completely and produce 1 mole of Fe and 0.5 moles of Al2O3.

Answer 2

Molar ratio of Fe to Al is 2:2.

Step-by-step explanation:

Wherever we write the chemical equation it must be a balanced one and the states of all the reactants and products to be mentioned, so that the reaction can be clearly understood. To write the molar ratio of the one of the reactant and product, we have to use the balanced equation as, here 2 moles of Al is required to produce 2 moles of iron (Fe).

Fe₂O₃(s) + 2 Al(s) → 2 Fe(s) + Al₂O₃(s)

So the molar ratio of Fe to Al is 2:2.