Question

Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly because of the electrostatic charged on the hairspray droplets. If the two drops of hairspray repel each other with a force of 9.0 x 10 (exponent -9)Newtons at a distance of 0.070cm, what is the charge on each of the equally charged drops of hairspray?

Answer 1

`7.0\cdot 10^(-13)C`

Step-by-step explanation:

The magnitude of the electrostatic force between two charged objects is

`F=k(q_1 q_2)/(r^2)`

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

The force is attractive if the charges have opposite sign and repulsive if the charges have same sign.

In this problem, we have:

`r=0.070 cm =7\cdot 10^(-4) m` is the distance between the charges

`q_1=q_2=q` since the charges are identical

`F=9.0\cdot 10^(-9)N` is the force between the charges

Re-arranging the equation and solving for q, we find the charge on each drop:

`F=(kq^2)/(r^2)\\q=\sqrt{(Fr^2)/(k)}=\sqrt{((9.0\cdot 10^(-9))(7\cdot 10^(-4))^2)/(8.99\cdot 10^9)}=7.0\cdot 10^(-13)C`