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If a football player passes a football from 4 feet off the ground with an initial velocity of 36 feet per second, how long will it take the football to hit the ground? Use the equation h = −16t2 + 6t + 4. Round your answer to the nearest hundredth.

A)0.72
B) 0.65
C)0.35
D)0.27

1 Answer

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Option A: The football will take 0.72 seconds to hit the ground.

Step-by-step explanation:

Given that the equation is
h=-16 t^(2)+6 t+4

We need to determine how long will it take the football to hit the ground.

Let us substitute h = 0 in the above equation.

Thus, we have,


0=-16 t^(2)+6 t+4

Now, we shall simplifying the equation using the quadratic formula.

The formula is given by


x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}

Substituting the values
a=-16, b=6, c=4 in the above formula, we get,


t=\frac{-6 \pm \sqrt{6^(2)-4(-16) 4}}{2(-16)}

Simplifying, we get,


t=(-6 \pm √(36+256))/(-32)


t=(-6 \pm √(292))/(-32)


t=(-6 \pm 2√(73))/(-32)

Taking out 2 as a common term, we get,


t=-(2(-3 \pm √(73)))/(32)

Dividing, we get,


t=-(-3 \pm √(73))/(16)

Thus, the roots of the equation are
t=-(-3+√(73))/(16), t=(3+√(73))/(16)

Simplifying the roots of the equation, we have,


t=-0.35 and
t=0.72

Since, t cannot take a negative value, we have,


t=0.72

Therefore, the football will take 0.72 seconds to hit the ground.

Hence, Option A is the correct answer.

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