Question

If a circle in Quadrant IV of the coordinate plane is tangent to the x- and y-axes and has a radius of 2, what is its equation?

A. −2)2+(−2)2=4
B. (−2)2+(+2)2=4
C. (+2)2+(−2)2=4
D. (−2)2+(+2)2=2

Answer 1

the answer would be B

Explanation:

Answer 2

B. (x - 2)^2 + (y + 2)^2 = 4.

Explanation:

The general form of the equation is

(x - a)^2 + (y - b)^2 = r^2 where (a,b) is the center and r is the radius of the circle.

The radius is 2 so r^2 = 4.

The center of the circle is at (2, -2) so the equation is:

(x - 2)^2 + (y + 2)^2 = 4.