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△ABC is inscribed in a circle such that vertices A and B lie on a diameter of the circle. If the length of the diameter of the circle is 13 and the length of chord BC is 5, find length AC.

The length AC is

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Answer:

AC=12

Explanation:

If vertices A and B lie on a diameter of the circle means that angle of triangle on the vertice C is 90, si this is right triangle. Now we can use Pitagora’s theorem to find AC.

AB^2=AC^2+BC^2

13^2=AC^2+5^2

169=AC^2+25

AC^2=169-25=144

AC=12

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