Question

On jan 1 the sum of $.01 would be in your account. On jan 2 that would become $.02 one jan 3, it would be $.04. On jan 4 it would be $.08... And so on, doubling each day. Whatever the amount is on jan 31st would be your compensation for the entire yearand you would receive no additional salary create a formula

Answer 1

Explanation:

As we know:

Day 1 = 0.1

Day 2= 0.2 = 0.1*2 = 0.1*
`2^(1)`

Day 3 = 0.4 = 0.2*2 = 2*2*0.1 = 0.1*
`2^(2)`

.........

So we can find down the general term of this sequence is:

A = 0.1*
`2^(n-1)`

Answer 2

The question is incomplete. I think the full question is "On jan 1 the sum of $.01 would be in your account. On jan 2 that would become $.02 one jan 3, it would be $.04. On jan 4 it would be $.08... And so on, doubling each day. Whatever the amount is on jan 31st would be your compensation for the entire year and you would receive no additional salary. Create a formula that shows how the daily sum can be determined from Jan2 to Jan 31st," The answer is a Geometric Progression of x, 2x ,4x,8x,...etc

Explanation:

For a sum to be 0.01 in JAN 1, 0.02 Jan 2, by Jan 31 the sum would have been as indicated in the attachment which contains for 30 days while the last day in January will double the one on January 30 which gives 10,737,418.42 dollars