Question

An iron chloride compound contains 55.85 grams of iron and 106.5 grams of chlorine. What is the most likely empirical formula for this compound?

Answer 1

`FeCl_(3)`

Step-by-step explanation:

`Moles =\frac {Given\ mass}{Molar\ mass}`

mass of Fe = 55.85 g

Molar mass of Fe = 55.85 g/mol

Moles of Fe = 55.85 / 55.85 = 1

mass of Cl = 106.5 g

Molar mass of Cl = 35.5 g/mol

Moles of Cl = 106.5 / 35.5 = 3

Taking the simplest ratio for Fe and Cl as:

1 : 3

The empirical formula is =
`FeCl_(3)`