Question

Bill Board is trying to reduce his sodium intake to an average of 2300 mg. He records his sodium intake for 4 days. The amounts are 2150 mg, 3005 mg, 2700 mg, and 2315 mg. What is the patient's average daily intake of sodium for those 4 days? What would his 5th day sodium intake need to be to drop him below an average of 2300 mg

Answer 1

A. average = 2542.5mg

B. The 5th day intake should be less than 1330mg

Step-by-step explanation:

Given the daily intake to be : 3005, 2700, 2315, 2150

Average =( 3005+ 2700+ 2315 + 2150)/4

Average = 10170/4

= 2542.5 mg

Let the 5th day intake be X

(X + 10,170)/5 <2300

X + 10,170 <5(2300)

X< 11,500 - 10,170

X < 1330mg

Answer 2

His average for 4 days is 2542.5 mg

Intake of 5th day has to be less than 1330 mg

Step-by-step explanation:

In order to find the average we take the sum of intakes for 4 day ans then divide it by total number of day which is 4 days.

Average = (2150 + 3005 + 2700 + 2315) / 4

Average = 10170/4

Average = 2542.5 mg

To find the 5th day intake such that average is below 2300 mg:

Let 5th day intake = x

We apply the same method to find the average by taking the sum of intakes for 5 days and then dividing the total with 5 days now. This average has to be less than 2300 mg therefore we use the following method:

(2150 + 3005 + 2700 + 2315 + x ) / 5 < 2300

2300 = (10170 + x)/ 5 < 2300

10170 + x < 11500

x < 11500 - 10170

x < 1330 mg