Question

Find the magnitude of vector v.
Given: initial point = (1,3) , terminal point = (-1,-2)

Answer 1

`√(29) units`

Explanation:

The magnitude of the vector with the initial point (1,3) and terminal point (-1,-2) can be calculated using;

`| \vec v| = √((x_2-x_1)^2 + (y_2-y_1)^2)`

We substitute the coordinates of the initial and terminal points to get:

`| \vec v| = √(( - 1-1)^2 + ( - 2-3)^2)`

We simplify to get:

`| \vec v| = √(( -2)^2 + ( - 5)^2)`

`| \vec v| = √(4 + 25)`

`| \vec v| = √(29)`

`| \vec v| = 5.39 \: units`