Question

Help on number 8 please!

Answer 1

(-a2b2c2)/(-3abc2)
= (-1/-3)(a2/a)(b2/b)(c2/c2)
=(1/3)[a^(2-1)][b^(2-1)][c^(2-2)]
= (1/3)(a)(b)(1)
=ab/3
Answer = ab/3

Answer 2

ab/3

Explanation:

I don't really know how to explain.

Μα†hway

hope this helps!