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What is the pH of 5.34 x 10^-6 M NaOH?

User Highend
by
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1 Answer

2 votes

Answer:

The pH is 8.73

Step-by-step explanation:

In water,


p^(H) + p^(0H) = 14


p^(H) = 14 - p^(0H)


p^(0H) = -log_(10)(H0^(-))

Thus,


p^(p0H) = -log_(10)(5.34×10^(-6))


p^(0H) = -(-5.27)


p^(0H) = 5.27)

Hence, we substitute;


p^(H) = 14 - p^(0H)

pH = 14 - 5.27

pH = 8.73

User Dzuc
by
7.5k points

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