Answer:
The capacitance is 1.75 nF
Step-by-step explanation:
From the question we are given that
The inner radius is
![r_(in) = 0.001](https://img.qammunity.org/2021/formulas/physics/college/ow4x3gwtic97kprpty23mv4ln3p2arbwxa.png)
The outer radius is
![r_(out) = 0.0011 \ m](https://img.qammunity.org/2021/formulas/physics/college/l4td4w48qw6wjr7xkb4ewqhfoxz7v1rqnc.png)
Length of the capacitor is
![L = 1m](https://img.qammunity.org/2021/formulas/physics/college/1cei4txc2o7a7inovtdzb2t4esjsuc9hzr.png)
The dielectric constant is
![Di = 2 \ for \ 0 < \phi < \pi](https://img.qammunity.org/2021/formulas/physics/college/bq6hmniaezekx66nhyjmelfob988356qs6.png)
The dielectric constant is
![Di_2 = 4 \ for \ \pi < \phi < 2\pi](https://img.qammunity.org/2021/formulas/physics/college/vzzch91jtwrh56ptffxuj90abcpp4402qg.png)
Generally the capacitance of a capacitor can be mathematically represented as
![C = (\pi \epsilon_0 Di_1 L)/(ln(r_(out))/(r_(in)) ) + (\pi \epsilon_0 Di_2L)/(ln(r_(out))/(r_(in)) )](https://img.qammunity.org/2021/formulas/physics/college/eaj6tst0aa07zb577nvxd3xqehkeq63mjl.png)
![= (\pi \epsilon_0 L (Di_1 + Di_2))/(ln(r_(out))/(r_(in)) )](https://img.qammunity.org/2021/formulas/physics/college/vzkk7cf14ftsox728jqrbb8lgtpw5jatcr.png)
![= ((3.142)(8.85*10^(-12))(1)(2+4))/(ln(0.0011)/(0.001) )](https://img.qammunity.org/2021/formulas/physics/college/3u1tvwa6872c0fxzfk3zxyqa882tuqdt9o.png)
![=1.75*10^(-9) F](https://img.qammunity.org/2021/formulas/physics/college/wa22pfpz3ezk5eju6k5akgqmugpi6mu7tc.png)
![1.75nF](https://img.qammunity.org/2021/formulas/physics/college/6dbzb8fm7ig76zzv780nd0hwjmfwri2h8n.png)