Ans: 671.4 J
In nitric oxide,
Specific heat capacity (s) = 0.746 J/g°C
Mass (m) = 90 g
Initial temperature (t1) = -20°C
Final temperature (t2) = -10°C
Change in temperature (dt) = t2 - t1
= -10°C - (-20°C)
= -10°C + 20°C
= 10°C,,
.•. dt = 10°C
Amount of heat required (Q) =? (Joule)
Using heat equation,
Q= m*s*dt
= 90 * 0.746 * 10
= 671.4 J
Hence 671.4 Joules of heat is required.