1 Answer

Dewd · Answer 1 · 2021-09-20T01:10:07+0000

Answer:

$\boxed { (7)/(5)y } \to \: \boxed {y+ (2)/(5)y }$

$\boxed { (3)/(5)y } \to \: \boxed {y - (2)/(5)y }$

Explanation:

We need to simplify

y + (2)/(5)y

We collect LCM to get;

(5y + 2y)/(5) = (7y)/(5)

Therefore:

$\boxed { (7)/(5)y } \to \: \boxed {y+ (2)/(5)y }$

Also we need to simplify:

y - (2)/(5)y

We collect LCM to get;

y - (2)/(5)y = (5y - 2y)/(5) = (3)/(5) y

Therefore

$\boxed { (3)/(5)y } \to \: \boxed {y - (2)/(5)y }$

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