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Two number cubes are rolled for two separate events:

Event A is the event that the sum of numbers on both cubes is less than 10.
Event B is the event that the sum of numbers on both cubes is a multiple of 3.
Complete the conditional-probability formula for event B given that event A occurs first by writing A and B in the blanks:

User Tornic
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1 Answer

5 votes

Answer:

11/30

Explanation:

P(B/A) = P(B^A)/P(A)

P(A) = 30/36 = 5/6

P(B^A) = (2+5+4)/36 = 11/36

11/36 ÷ 30/36

11/30 or 0.3667

User Nibor
by
8.6k points

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