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SPEAR is a storage ring at the Stanford Linear Accelerator which has a circulating beam of electrons that are moving at nearly the speed of light (2.998 108 m/s). If a similar ring is about 68.0 m in diameter and has a 0.37 A beam, how many electrons are in the beam

User Alagner
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1 Answer

5 votes

Answer:

The no. of electron in the beam =
1.64*10^(12)

Step-by-step explanation:

Given :

The diameter of circular ring = 68 m.

The current flowing in the beam = 0.37 A

Speed of light =
3*10^(8) ms^(-1)

We know that the current is equal to the charge per unit time.


I = (Q)/(t)


Q=It

Here given in the question, electron revolving in a circle with the diameter


d = 68m

⇒ Time take to complete one round
(t) =
(\pi d )/(v)


Q = (I\pi d )/(v)


Q = (0.37 * 3.14 * 68)/(3 * 10^(8) )


Q = 26.33 * 10^(-8)

Now, for finding the no. of electron we have to divide
Q to the charge of the electron
q = 1.6 * 10^(-19)


n =
(26.33 * 10^(-8) )/(1.6 * 10^(-19) )


n = 1.64 * 10^(12)

Thus, the no. of electron in the beam is
1.64 * 10^(12).

User Redoff
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