Question

A 4.0 cm × 4.2 cm rectangle lies in the xy-plane. You may want to review (Pages 664 - 668) . Part A What is the electric flux through the rectangle if E⃗ =(150ı^−200k^)N/C? Φe = N⋅m2/C Previous AnswersRequest Answer Incorrect; Try Again; 5 attempts remaining Part BPart complete What is the electric flux through the rectangle if E⃗ =(150ı^−200ȷ^)N/C? Φe = 0 N⋅m2/C

Answer 1

Step-by-step explanation:

Area, A = 4 cm x 4.2 cm = 16.8 cm²

A).

`\overrightarrow{E}=150\widehat{i}-200\widehat{k}`

Area is in x y plane so

`\overrightarrow{A}=16.8* 10^(-4)\widehat{k}`

Electric flux,

`\phi =\overrightarrow{E}.\overrightarrow{A}`

`\phi =\left ( 150\widehat{i}-200\widehat{k} \right ).\left (16.8* 10^(-4)\widehat{k} \right )`

Ф = 0.336 Nm²/C

B).

`\overrightarrow{E}=150\widehat{i}-200\widehat{j}`

`\phi =\overrightarrow{E}.\overrightarrow{A}`

`\phi =\left ( 150\widehat{i}-200\widehat{j} \right ).\left (16.8* 10^(-4)\widehat{k} \right )`

Ф = 0 Nm²/C