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Oxygen gas is collected over water. The total pressure (the O2 pressure the water vapor pressure) is 736 torr. The temperature of the water is such that the water vapor pressure is 46 torr. What is the partial pressure of the oxygen gas in torr

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Answer:

The value of the partial pressure of the oxygen
P_{O_(2) } = 690 torr

Step-by-step explanation:

Total pressure of the mixture of gases = 736 torr

The partial pressure of water vapor = 46 torr

From the law of pressure we know that

Total pressure = The partial pressure of water vapor + The partial pressure of oxygen
O_(2)

Put the values of pressures in above equation we get,

⇒ 736 = 46 +
P_{O_(2) }


P_{O_(2) } = 736 - 46


P_{O_(2) } = 690 torr

This is the value of the partial pressure of the oxygen.

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