Answer:
1.07×10⁻⁵ Wb
Step-by-step explanation:
Using
Φ = BAcosθ.................. Equation 1
Where Φ = magnetic Flux, B = magnetic Field, A = Area of the rectangular loop, Angle between the loop and the Field.
But
A = L×W........................ Equation 2
Where L = Length, W = Width.
Substitute equation 2 into equation 1
Φ = BLWcosΦ................ Equation 3
Given: B = 0.77 T, L = 0.4 cm = 0.004 m, W = 0.4 cm = 0.004 m, Ф = 30°
Substitute into equation 3
Ф = 0.77(0.004)(0.004)cos30
Ф = 1.07×10⁻⁵ Wb.
Hence the magnetic Field through the loop = 1.07×10⁻⁵ Wb.