Answer:
initial current I₀ = 0.0123 A
RC time constant τ = 0.00075 sec
current after one time constant I = 0.00452 A
voltage on the capacitor after one time constant V = 3.89 V
Step-by-step explanation:
Given that,
Voltage = 6.16 V
Resistance = 500 Ω
Capacitance = 1.5 µF
(a) What is the initial current?
The initial current can be found using
I₀ = Voltage/Resistance
I₀ = 6.16/500
I₀ = 0.0123 A
(b) What is the RC time constant?
The time constant τ provides the information about how long it will take to charge the capacitor.
τ = R*C
τ = 500*1.5x10⁻⁶
τ = 0.00075 sec
(c) What is the current after one time constant?
I = I₀e^(-τ/RC)
I = 0.0123*e^(-1) (0.00075/0.00075 = 1)
I = 0.00452 A
(d) What is the voltage on the capacitor after one time constant?
V = V₀(1 - e^(-τ/RC))
Where V₀ is the initial voltage 6.16 V
V = 6.16(1 - e^(-1))
V = 6.16*0.63212
V = 3.89 V
That means the capacitor will charge up to 3.89 V in one time constant