Question

Two long, parallel wires are separated by a distance of 3.30 cm. The force per unit length that each wire exerts on the other is 5.00×10−5 N/m, and the wires repel each other. The current in one wire is 0.620 A.

a. What is the current in the second wire?
b. Are the two currents in the same direction or in opposite directions?

Answer 1

Answer with Explanation:

We are given that

Distance between two parallel long wires=r=3.3 cm=
`(3.3)/(100)=0.033m`

1 m=100 cm

`(F)/(l)=5* 10^(-5) N/m`

`I_1=0.62 A`

a.We have to find the current in the second wire.

We know that

`(F)/(l)=(2\mu_0I_1I_2)/(4\pi r)`

Using the formula

`5* 10^(-5)=(2* 10^(-7)* 0.62* I_2)/(0.033)`

Where
`(\mu_0)/(4\pi)=10^(-7)`

`I_2=(5* 10^(-5)* 0.033)/(2* 10^(-7)* 0.62)`

`I_2=13.3 A`

Hence, the current in the second wire=13.3 A

b.We are given that the wires repel each other.When the current carrying in the wires in opposite direction then, the wires repel to each other.

Hence,the two currents in opposite directions.