Answer:
Step-by-step explanation:
Given that,
Sphere of radius R
At radial distance ¼R it has an electric field of Eo
Magnitude of electric field E at r=2R
Solution
electric field is given as
E=KQ/r²
Now at R,
E=KQ/R²
When, at r=R/4 inside the sphere is given as
Eo=kQ/R³ • R/4
Eo=kQ/4R²
When, r =2R
Then,
E=kQ/(2R)²
E=kQ/4R²
Comparing this to Eo
Then, E=Eo
Then, the electric field at r=2R is equal to the electric field at r=R/4