Question

Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 7.50 cm apart. You see an object jump from side to side by 0.95 degree as you blink back and forth between your eyes. How far away is the object?

Answer 1

Distance of the object from eye is approx 4.52 m

Step-by-step explanation:

As we know that the object subtend a small angle on both the eyes which is given as

`\theta = 0.995 degree`

now we know that the distance between two eyes is given as

d = 7.50 cm

so we have

`angle = (arc)/(Radius)`

so here the radius is same as the distance from eye while arc is the distance between two eyes

so we have

`0.95 (\pi)/(180) = (7.50)/(R)`

`R = 452 cm`