Answer:
The hang time is 0.95 s
Step-by-step explanation:
Spud Webb has a height of 5 feet 8 inches and is one of the shortest basketball players to play in the NBA.
He could make an amazing vertical leap of 1.1 m off the ground. For such a leap to calculate the hang time(the time spent in the air after leaving the ground and before touching down again), we use the formula:

Where S is the distance traveled, u is the initial velocity, t is the time taken and g is the acceleration due to gravity.
Given that:
g = 9.8 m/s²
S =

u = 0

Substituting values:

Dividing through by -4.9 we get:


t = 0.474 s
The hang time = 2t = 2 × 0.474 = 0.95 s
The hang time is 0.95 s