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To model a tornado, superimpose the stream function for a vortex (Eq. 6.91) and a source (Eq. 6.83). Assume that the circulation is 8000 m2 /s and the pressure at the radius of 40 m is 2 kPa less than atmospheric

User Bernhardw
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Answer:

The stream function for this potential flow is -4696.8

Step-by-step explanation:

Given that,

Circulation = 8000 m²/s

Radius = 40 m

Pressure = 2 kPa

Suppose the determine the stream function for this potential flow

We need to calculate the stream function

Using formula of stream function


\Psi=-((\Gamma)/(2\pi))ln(r)

Where, Γ = circulation

r = radius

Put the value into the formula


\Psi=-(8000)/(2\pi)* ln(40)


\Psi=-4696.8

Hence, The stream function for this potential flow is -4696.8

User AwongCM
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