Answer:
The answer if 3/64 or 4.69%
Step-by-step explanation:
B-: Black; bb: white
Two heterozygote rabbits: 2^2 = 4 possible gametes.
- P: Bb x Bb
- F1: 1/4 BB; 2/4 Bb; 1/4 bb
- there are 3/4 black and 1/4 white
The probability that their offspring are given birth following the order white - black - white is:
- 1/4 white * 3/4 black * 1/4 white = 3/64 = 4.6875%