Question

A wooden block of mass= 0.80kg is pulled along a rough horizontal surface with a force of 20N, the block experiences an acceleration of 5ms^-2. what is the magnitude of the frictional force?

Answer 1

`F_(r) = 16 \ \rm N`.

Step-by-step explanation:

Given data:

Mass of the wooden block,
`m = 0.80 \ kg`

Applied force,
`F = 20 \ \rm N`

Acceleration,
`a = 5 \ m/s^(2)`

Let the magnitude of the frictional force be
`F_(r).`

On applying Newton's second law of motion,

`ma = F- F_(r)`

`0.80 * 5 = 20 - F_(r)`

`\Rightarrow \ F_(r) = 16 \ \rm N.`

Answer 2

The answer is 200 I am sure