Answer: 1.9394m/s
Explanation: m1 (mass of 3 billiard ball) = 0.16kg
U1(initial velocity of the 3 billiard ball) = 4.0m/s
M2 (mass of the cue ball) = 0.17kg
U1 (initial velocity of the cue ball) = 0m/s
Final velocities of both the cue ball and 3 billiard ball after collision = ?
According to the principle of conservation of linear momentum, total momenta before collision = total momenta after collision:
M1U1 + M2U2 = (M1+M2)V
0.16*4.0 + 0.17* 0 = (0.16 + 0.17)V
0.64 + 0 = 0.33V
V = 0.64/0.33 = 1.9394m/s