Answer:
an improvement in efficiency is observed with η = 99.99%
Step-by-step explanation:
the voltage can be calculated using the formula: the detection time can be calculated using the equation:
t1 = V/Q = 10000/1000 = 10 days
t2 = 20000/1000 = 20 days
t3 = 6000/1000 = 6 days
the exit of the organisms will be:
1rd pond = 10^6/(1+(10*10)) = 90909.1 org/mL
2nd pond = 90909.1/(1+(1*20)) = 4329 org/mL
3rd pond = 4329/(1+(1*6)) = 618.4 org/mL
η = ((Cin-Cout)/Cin)*100 = ((10^6-618.4)/(10^6))*100 = 99.93%
detection time t = 12000/1000 = 12 days
Cout1 = 10^6/(1+(1*12)) = 76923.1
Cout2 = 76923.1/(1+(1*12)) = 5917.2
Cout3 = 5917.2/(1+(1*12)) = 455.2
η = ((10^6-455.2)/(10^6))*100 = 99.99%
an improvement in efficiency is observed