Question

Bill Board is trying to reduce his sodium intake to an average of 2300 mg.

He records his sodium intake for 4 days.
The amounts are 2150 mg, 3005 mg, 2700 mg, and 2315 mg.
What is the patient’s average daily intake of sodium for those 4 days?
What would his 5th day sodium intake need to be to drop him below an average of 2300 mg

Answer 1

mean average = 2542.5 mg

1330 mg

Step-by-step explanation:

The patient's average daily intake of sodium for those 4 days can be calculated by taking the mean average of the sample amounts given over the number of the total days.

`mean average = (2150+3005+2700+2315)/(4)`

`mean average = (10170)/(4)`

mean average = 2542.5 mg

Therefore the patient's average daily intake of sodium for those 4 days = 2542.5 mg

What is the patient’s average daily intake of sodium for those 4 days?

What would his 5th day sodium intake need to be to drop him below an average of 2300 mg

given that mean average = 2300; we can also determine the fifth day sodium intake as follows:

`mean average = (2150+3005+2700+2315+y)/(5)\\2300 = (2150+3005+2700+2315+y)/(5)`

`2300*5 =2150+3005+2700+2315+y`

`11500 = 10170 +y`

`11500-10170 =y`

y = 1330 mg

Hence, his sodium intake for the fifth day will be 1330 in order to drop him below an average of 2300 mg