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A 2.00 L container of nitrogen has a pressure of 3.2 atm. What volume would the container be at if the pressure decreased to 1.00 atm

1 Answer

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Answer:

The volume would be 6,4 L

Step-by-step explanation:

We use the Boyle Mariotte formula, according to which for a certain mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1 = P2xV2

V2= (P1xV1)/P2= (3,2 atm x 2, 00 L)/1,00 atm= 6,4 L

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