Question

Problem 8: Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.65 T.

What is the potential difference in volts required in the first part of the experiment to accelerate electrons to a speed of 6 1 × 107 m/s?

Answer 1

10581.59 V

Step-by-step explanation:

We are given that

Magnetic field=B=0.65 T

Speed of electron=
`v=6.1* 10^7m/s`

Charge on electron,
`q=e=1.6* 10^(-19) C`

Mass of electron,
`m_e=9.1* 10^(-31) kg`

We have to find the potential difference in volts required in the first part of the experiment to accelerate electrons.

`V=(v^2m_e)/(2e)`

Where V=Potential difference

`m_e=`Mass of electron

v=Velocity of electron

Using the formula

`V=((6.1* 10^7)^2* 9.1* 10^(-31))/(2* 1.6* 10^(-19))`

`V=10581.59 V`

Hence, the potential difference=10581.59 V