Answer:
The force required to push to stop the car is 288.67 N
Step-by-step explanation:
Given that
Mass of the car, m = 1000 kg
Initial speed of the car, u = 1 m/s
The car and push on the hood at an angle of 30° below horizontal,
![\theta=30^(\circ)](https://img.qammunity.org/2021/formulas/physics/college/x55tnamvwth8ipldmu9uxf4v0gm5c926d1.png)
Distance, d = 2 m
Let F is the force must you push to stop the car.
According work energy theorem theorem, the work done is equal to the change in kinetic energy as :
![W=(1)/(2)m(v^2-u^2)F* d=(1)/(2)m(v^2-u^2)](https://img.qammunity.org/2021/formulas/physics/college/2pjn58z5e3hp2sjp24gqhg9nlsi3nhwnqn.png)
![v = 0](https://img.qammunity.org/2021/formulas/physics/college/tosoj3i6j3v0bqpfb46x8z9ahfua4alhqu.png)
![Fd\ cos\theta=(1)/(2)m(u^2) F=((1)/(2)m(u^2))/(d\ cos\theta)F=((1)/(2)* 1000* (1)^2)/(2\ cos(30))F = -288.67 N](https://img.qammunity.org/2021/formulas/physics/college/umjteh9lowwoxak660a5vv26ghxe1mjv86.png)
The force required to push to stop the car is 288.67 N